You will be asked to conduct a Chi-Square analysis using the table below by using the Five Step process, Be sure to download this Excel file and complete the tables
Compute your expected frequencies using the method I showed you in Excel and upload your spreadsheet. I want to see the following:
Using the spreadsheet you downloaded, please complete the following:
- A table of expected frequencies (5pts)
- A table of chi-square square statistics (5pts)
- State your chi-square statistic (2pts)
- Report your degrees of freedom (2pts)
- Run your chi-square test for your p value (2pts)
- Be sure to show your work (input the commands in each cell) (5pts)
Sheet1
| Should Marijuana Be Legal | ||||||||
| So, for your expected frequencies, you are going to multiply the row marginal (male or female) by the column marginal for either "yes" or "no" and divide by the total (210). | ||||||||
| Observed | Expected | |||||||
| Legalize Marijuana | Legalize Marijuana | |||||||
| Gender | Yes | No | Row Marginal | Gender | Yes | No | Row Marginal | |
| Male | 50 | 24 | 74 | Male | 46.5142857143 | 74 | ||
| Female | 82 | 54 | 136 | Female | 136 | |||
| Column Marginal | 132 | 78 | 210 | Column Marginal | 132 | 78 | 210 | |
| Chi-Square Statistics | ||||||||
| Legalize Marijuana | ||||||||
| Gender | Yes | No | Row Marginal | |||||
| Male | 0.2612144612 | X2 statistic | ||||||
| Female | Df= | (r-1)(c-1) | ||||||
| Column Marginal | P value | |||||||
| Remember: to calculate your chi-square statistic per group, take the (observed frequency- expected frequency)²/ expected frequency | ||||||||
,
If we suspect that there is no relationship between gender and support of legalizing marijuana, what would be the best alternative hypothesis?
A. There is a relationship between gender and support of legalizing marijuana.
B. Gender has no influence on support of legalizing marijuana
C. There is a relationship between gender and marijuana use
D. Not enough data
Which of the following is the correct degrees of freedom in the table below?
A. 4
B. 3
C. 2
D. 1
What is our critical value for our degrees of freedom in the above referenced table if the alpha level is set at .05? The decision rule is that if X2 > this number, the null hypothesis will be rejected.
A. 5.99
B. 3.841
C. 2.71
D. 4.35
Given the above information, we fail to reject the null hypothesis (or simply accept that the null hypothesis is true in the current case).
A. True
B. False